Multiple Tests and if
-else
Statements
Often you want to distinguish between more than two distinct cases,
but conditions only have two possible results, true
or false
,
so the only direct choice is between two options. As anyone who has
played “20 Questions” knows, you can distinguish more cases with
further questions. If there are more than two choices, a single
test may only reduce the possibilities, but further tests can
reduce the possibilities further and further. Since most any kind
of statement can be placed in the sub-statements in
an if
-else
statement, one
choice is a further if
or if
-else
statement.
For instance consider a
function to convert a numerical grade to a letter grade, ‘A’, ‘B’,
‘C’, ‘D’ or ‘F’, where the cutoffs for ‘A’, ‘B’, ‘C’, and ‘D’ are
90, 80, 70, and 60 respectively. One way to write the function
would be to test for one grade at a time, and resolve all the
remaining possibilities inside the next else
clause.
If we do this consistent with our indentation conventions so far:
static char letterGrade(double score)
{
char letter;
if (score >= 90) {
letter = 'A';
}
else { // grade must be B, C, D or F
if (score >= 80) {
letter = 'B';
}
else { // grade must be C, D or F
if (score >= 70) {
letter = 'C';
}
else { // grade must D or F
if (score >= 60) {
letter = 'D';
}
else {
letter = 'F';
}
} //end else D or F
} // end of else C, D, or F
} // end of else B, C, D or F
return letter;
}
This repeatedly increasing indentation with an if
statement in
the else
clause can be annoying and distracting. Here is a preferred
alternative in this situation, that avoids all this further
indentation:
Combine each else
and following if
onto the same line,
and note that the if
part after each else is just a single
(possibly very complicated) statement. This allows the elimination of
some of the braces:
/// Return letter grade for score.
static char letterGrade(double score)
{
char letter;
if (score >= 90) {
letter = 'A';
}
else if (score >= 80) { // grade must be B, C, D or F
letter = 'B';
}
else if (score >= 70) { // grade must be C, D or F
letter = 'C';
}
else if (score >= 60) { // grade must D or F
letter = 'D';
}
else {
letter = 'F';
}
return letter;
}
A program testing the letterGrade function is in example program grade1/grade1.cs.
See Grade Exercise.
As in a basic if
-else
statement, in the general format,
if (
condition1 ) {
}
else if (
condition2 ) {
}
else if (
condition3 ) {
}
else { //
no condition!}
exactly one of the statement blocks gets executed:
If some condition is true,
the first block following a true condition is executed.
If no condition is true,
the else
block is executed.
Here is a variation. Consider this
fragment without a final else
:
if (weight > 120) {
Console.WriteLine("Sorry, we can not take a suitcase that heavy.");
}
else if (weight > 50) {
Console.WriteLine("There is a $25 charge for luggage that heavy.");
}
This statement only prints one of two lines if there is a problem with the weight of the suitcase. Nothing is printed if there is not a problem.
If the final else
clause is omitted from the general if
… else if
…
pattern above, at most one block after a condition
is executed: That is the block after the first true condition.
If all the conditions are false, none of the statement blocks
will be executed.
It is also possible to embed if
-else
statements inside other if
or
if
-else
statements in more complicated patterns.
Sign Exercise
Write a program sign.cs
to ask the user for a number. Print out
which category the number is in: "positive"
, "negative"
, or
"zero"
.
Grade Exercise
Copy grade1/grade1.cs to grade2.cs
in your own project.
Modify
grade2.cs
so it has an equivalent version of the letterGrade
function that tests in the opposite order, first for F, then D, C,
…. Hint: How many tests do you need to do? 1
Be sure to run your new version and test with different inputs that test all the different paths through the program.
Be careful for edge cases: Test the grades on the “edge” of a change in the result.
Wages Exercise
Modify the wages1/wages1.cs or the wages2/wages2.cs
example to create a
program wages3.cs
that assumes people are paid double time for
hours over 60. Hence they get paid for at most 20 hours overtime at
1.5 times the normal rate. For example, a person working 65 hours
with a regular wage of $10 per hour would work at $10 per hour for
40 hours, at 1.5 * $10 for 20 hours of overtime, and 2 * $10 for
5 hours of double time, for a total of
10*40 + 1.5*10*20 + 2*10*5 = $800.
You may find wages2/wages2.cs easier to adapt than wages1/wages1.cs.
Caution: Be sure to thoroughly test your final program version. It is easy to add new features that work by themselves, but break a part that worked before! In particular in a program with decisions, make sure you test with enough different data to check all lines of your program.
- 1
4 tests to distinguish the 5 cases, as in the previous version